The Sanskrit Reader Companion

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Input: tarkayāmāsa bhaimīti kāraṇair upapādayan

Sentence: तर्कयामास भैमीति कारणैः उपपादयन्
may be analysed as:

Solution 3 : ✓
[ tarkayā

[tarka]{f. sg. i.}

⟨⟩]
[ mā

[asmad]{* sg. acc.}

⟨ā|ā → ā⟩]
[ āsa

[as_1]{pft. ac. pl. 2 \| pft. ac. sg. 3 \| pft. ac. sg. 1}
[as_2]{pft. ac. pl. 2 \| pft. ac. sg. 3 \| pft. ac. sg. 1}

⟨⟩]
[ bhaimī

[bhaima]{iic.}

⟨ī|ī → ī⟩]
[ īti

[īti]{n. sg. acc. \| n. sg. nom.}

⟨⟩]
[ kāraṇaiḥ

[kāraṇa]{n. pl. i.}

⟨ḥ| → ḥ⟩]
[ upapādayan

[upa-pādayat { ca. ppr. ac. }[upa-pad_1]]{m. sg. nom.}

⟨⟩]

Solution 4 : ✓
[ tarkayā

[tarka]{f. sg. i.}

⟨⟩]
[ mā

[asmad]{* sg. acc.}

⟨ā|ā → ā⟩]
[ āsa

[as_1]{pft. ac. pl. 2 \| pft. ac. sg. 3 \| pft. ac. sg. 1}
[as_2]{pft. ac. pl. 2 \| pft. ac. sg. 3 \| pft. ac. sg. 1}

⟨⟩]
[ bhaimī

[bhaima]{iic.}

⟨ī|ī → ī⟩]
[ īti

[īti]{n. sg. voc.}

⟨⟩]
[ kāraṇaiḥ

[kāraṇa]{n. pl. i.}

⟨ḥ| → ḥ⟩]
[ upapādayan

[upa-pādayat { ca. ppr. ac. }[upa-pad_1]]{m. sg. nom.}

⟨⟩]

Solution 7 : ✓
[ tarkayā

[tarka]{f. sg. i.}

⟨⟩]
[ mā

[asmad]{* sg. acc.}

⟨ā|a → ā⟩]
[ asa

[as_2]{imp. [1] ac. sg. 2}

⟨⟩]
[ bhaimī

[bhaima]{iic.}

⟨ī|ī → ī⟩]
[ īti

[īti]{n. sg. acc. \| n. sg. nom.}

⟨⟩]
[ kāraṇaiḥ

[kāraṇa]{n. pl. i.}

⟨ḥ| → ḥ⟩]
[ upapādayan

[upa-pādayat { ca. ppr. ac. }[upa-pad_1]]{m. sg. nom.}

⟨⟩]

Solution 8 : ✓
[ tarkayā

[tarka]{f. sg. i.}

⟨⟩]
[ mā

[asmad]{* sg. acc.}

⟨ā|a → ā⟩]
[ asa

[as_2]{imp. [1] ac. sg. 2}

⟨⟩]
[ bhaimī

[bhaima]{iic.}

⟨ī|ī → ī⟩]
[ īti

[īti]{n. sg. voc.}

⟨⟩]
[ kāraṇaiḥ

[kāraṇa]{n. pl. i.}

⟨ḥ| → ḥ⟩]
[ upapādayan

[upa-pādayat { ca. ppr. ac. }[upa-pad_1]]{m. sg. nom.}

⟨⟩]

4 solutions kept among 8
Filtering efficiency: 57%