Sanskrit Reader Companion

The Sanskrit Reader Companion

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Input: vinayāvanato bhūtvā kadācit sūtanandanaḥ

Sentence: विनयावनतः भूत्वा कदाचित् सूतनन्दनः
may be analysed as:

Solution 61 : ✓
[ vinaya

[vi-nī_1]{imp. [1] ac. sg. 2}

⟨a|a → ā⟩]
[ avan

[avat { ppr. [1] ac. }[av]]{m. sg. nom.}

⟨⟩]
[ ataḥ

[atas]{ind.}

⟨ḥ| → ḥ⟩]
[ bhūtvā

[bhū_1]{abs.}

⟨⟩]
[ kadācit

[kadācit]{ind.}

⟨⟩]
[ sūta

[sūta_2]{iic.}

⟨⟩]
[ nandanaḥ

[nandana]{m. sg. nom.}

⟨ḥ| → ḥ⟩]

Solution 64 : ✓
[ vinaya

[vi-nī_1]{imp. [1] ac. sg. 2}

⟨a|a → ā⟩]
[ avan

[avat { ppr. [1] ac. }[av]]{m. sg. nom.}

⟨⟩]
[ ataḥ

[atas]{ind.}

⟨ḥ| → ḥ⟩]
[ bhūtvā

[bhū_1]{abs.}

⟨⟩]
[ kadācit

[kadācit]{ind.}

⟨⟩]
[ sūta

[sūta_1 { pp. }[sū_1]]{iic.}

⟨⟩]
[ nandanaḥ

[nandana]{m. sg. nom.}

⟨ḥ| → ḥ⟩]

Solution 65 : ✓
[ vinaya

[vi-nī_1]{imp. [1] ac. sg. 2}

⟨a|a → ā⟩]
[ avan

[avat { ppr. [1] ac. }[av]]{m. sg. nom.}

⟨⟩]
[ ataḥ

[atas]{ind.}

⟨ḥ| → ḥ⟩]
[ bhūtvā

[bhū_1]{abs.}

⟨⟩]
[ kadā

[kadā]{ind.}

⟨⟩]
[ cit

[cit_2]{m. sg. nom. \| n. sg. acc. \| n. sg. nom. \| f. sg. nom.}

⟨⟩]
[ sūta

[sūta_2]{iic.}

⟨⟩]
[ nandanaḥ

[nandana]{m. sg. nom.}

⟨ḥ| → ḥ⟩]

Solution 68 : ✓
[ vinaya

[vi-nī_1]{imp. [1] ac. sg. 2}

⟨a|a → ā⟩]
[ avan

[avat { ppr. [1] ac. }[av]]{m. sg. nom.}

⟨⟩]
[ ataḥ

[atas]{ind.}

⟨ḥ| → ḥ⟩]
[ bhūtvā

[bhū_1]{abs.}

⟨⟩]
[ kadā

[kadā]{ind.}

⟨⟩]
[ cit

[cit_2]{m. sg. nom. \| n. sg. acc. \| n. sg. nom. \| f. sg. nom.}

⟨⟩]
[ sūta

[sūta_1 { pp. }[sū_1]]{iic.}

⟨⟩]
[ nandanaḥ

[nandana]{m. sg. nom.}

⟨ḥ| → ḥ⟩]

Solution 73 : ✓
[ vinaya

[vi-nī_1]{imp. [1] ac. sg. 2}

⟨a|a → ā⟩]
[ avan

[avat { ppr. [1] ac. }[av]]{m. sg. nom.}

⟨⟩]
[ ataḥ

[atas]{ind.}

⟨ḥ| → ḥ⟩]
[ bhūtvā

[bhū_1]{abs.}

⟨⟩]
[ kadā

[kadā]{ind.}

⟨ā|a → ā⟩]
[ acit

[acit]{m. sg. nom. \| n. sg. acc. \| n. sg. nom. \| f. sg. nom.}

⟨⟩]
[ sūta

[sūta_2]{iic.}

⟨⟩]
[ nandanaḥ

[nandana]{m. sg. nom.}

⟨ḥ| → ḥ⟩]

Solution 76 : ✓
[ vinaya

[vi-nī_1]{imp. [1] ac. sg. 2}

⟨a|a → ā⟩]
[ avan

[avat { ppr. [1] ac. }[av]]{m. sg. nom.}

⟨⟩]
[ ataḥ

[atas]{ind.}

⟨ḥ| → ḥ⟩]
[ bhūtvā

[bhū_1]{abs.}

⟨⟩]
[ kadā

[kadā]{ind.}

⟨ā|a → ā⟩]
[ acit

[acit]{m. sg. nom. \| n. sg. acc. \| n. sg. nom. \| f. sg. nom.}

⟨⟩]
[ sūta

[sūta_1 { pp. }[sū_1]]{iic.}

⟨⟩]
[ nandanaḥ

[nandana]{m. sg. nom.}

⟨ḥ| → ḥ⟩]

Solution 81 : ✓
[ vinaya

[vi-nī_1]{imp. [1] ac. sg. 2}

⟨a|a → ā⟩]
[ avanataḥ

[ava-nata { pp. }[ava-nam]]{m. sg. nom.}

⟨ḥ| → ḥ⟩]
[ bhūtvā

[bhū_1]{abs.}

⟨⟩]
[ kadācit

[kadācit]{ind.}

⟨⟩]
[ sūta

[sūta_2]{iic.}

⟨⟩]
[ nandanaḥ

[nandana]{m. sg. nom.}

⟨ḥ| → ḥ⟩]

Solution 84 : ✓
[ vinaya

[vi-nī_1]{imp. [1] ac. sg. 2}

⟨a|a → ā⟩]
[ avanataḥ

[ava-nata { pp. }[ava-nam]]{m. sg. nom.}

⟨ḥ| → ḥ⟩]
[ bhūtvā

[bhū_1]{abs.}

⟨⟩]
[ kadācit

[kadācit]{ind.}

⟨⟩]
[ sūta

[sūta_1 { pp. }[sū_1]]{iic.}

⟨⟩]
[ nandanaḥ

[nandana]{m. sg. nom.}

⟨ḥ| → ḥ⟩]

Solution 85 : ✓
[ vinaya

[vi-nī_1]{imp. [1] ac. sg. 2}

⟨a|a → ā⟩]
[ avanataḥ

[ava-nata { pp. }[ava-nam]]{m. sg. nom.}

⟨ḥ| → ḥ⟩]
[ bhūtvā

[bhū_1]{abs.}

⟨⟩]
[ kadā

[kadā]{ind.}

⟨⟩]
[ cit

[cit_2]{m. sg. nom. \| n. sg. acc. \| n. sg. nom. \| f. sg. nom.}

⟨⟩]
[ sūta

[sūta_2]{iic.}

⟨⟩]
[ nandanaḥ

[nandana]{m. sg. nom.}

⟨ḥ| → ḥ⟩]

Solution 88 : ✓
[ vinaya

[vi-nī_1]{imp. [1] ac. sg. 2}

⟨a|a → ā⟩]
[ avanataḥ

[ava-nata { pp. }[ava-nam]]{m. sg. nom.}

⟨ḥ| → ḥ⟩]
[ bhūtvā

[bhū_1]{abs.}

⟨⟩]
[ kadā

[kadā]{ind.}

⟨⟩]
[ cit

[cit_2]{m. sg. nom. \| n. sg. acc. \| n. sg. nom. \| f. sg. nom.}

⟨⟩]
[ sūta

[sūta_1 { pp. }[sū_1]]{iic.}

⟨⟩]
[ nandanaḥ

[nandana]{m. sg. nom.}

⟨ḥ| → ḥ⟩]

Solution 93 : ✓
[ vinaya

[vi-nī_1]{imp. [1] ac. sg. 2}

⟨a|a → ā⟩]
[ avanataḥ

[ava-nata { pp. }[ava-nam]]{m. sg. nom.}

⟨ḥ| → ḥ⟩]
[ bhūtvā

[bhū_1]{abs.}

⟨⟩]
[ kadā

[kadā]{ind.}

⟨ā|a → ā⟩]
[ acit

[acit]{m. sg. nom. \| n. sg. acc. \| n. sg. nom. \| f. sg. nom.}

⟨⟩]
[ sūta

[sūta_2]{iic.}

⟨⟩]
[ nandanaḥ

[nandana]{m. sg. nom.}

⟨ḥ| → ḥ⟩]

Solution 96 : ✓
[ vinaya

[vi-nī_1]{imp. [1] ac. sg. 2}

⟨a|a → ā⟩]
[ avanataḥ

[ava-nata { pp. }[ava-nam]]{m. sg. nom.}

⟨ḥ| → ḥ⟩]
[ bhūtvā

[bhū_1]{abs.}

⟨⟩]
[ kadā

[kadā]{ind.}

⟨ā|a → ā⟩]
[ acit

[acit]{m. sg. nom. \| n. sg. acc. \| n. sg. nom. \| f. sg. nom.}

⟨⟩]
[ sūta

[sūta_1 { pp. }[sū_1]]{iic.}

⟨⟩]
[ nandanaḥ

[nandana]{m. sg. nom.}

⟨ḥ| → ḥ⟩]

12 solutions kept among 100
Filtering efficiency: 88%