Sanskrit Reader Companion

The Sanskrit Reader Companion

✓ Show Summary of Solutions

Input: siṃhanādaṃ vinadyoccaiḥ śaṅkhaṃ dadhmau pratāpavān

Sentence: सिंहनादम् विनद्योच्चैः शङ्खम् दध्मौ प्रतापवान्
may be analysed as:

Solution 3 : ✓
[ siṃha

[siṃha]{iic.}

⟨⟩]
[ nādam

[nāda]{m. sg. acc.}

⟨⟩]
[ vinadya

[vi-nad]{abs. \| ca. abs.}

⟨a|u → o⟩]
[ uccaiḥ

[uccais]{adv.}

⟨ḥ| → ḥ⟩]
[ śam

[śam_3]{ind.}

⟨m|kh → ṅkh⟩]
[ kham

[kha]{n. sg. acc. \| n. sg. nom.}

⟨⟩]
[ dadhmau

[dham]{pft. ac. sg. 3 \| pft. ac. sg. 1}

⟨⟩]
[ pratāpavān

[pratāpavat]{m. sg. nom.}

⟨⟩]

Solution 6 : ✓
[ siṃha

[siṃha]{iic.}

⟨⟩]
[ nādam

[nāda]{m. sg. acc.}

⟨⟩]
[ vinadya

[vi-nad]{abs. \| ca. abs.}

⟨a|u → o⟩]
[ uccaiḥ

[ucca]{m. pl. i. \| n. pl. i.}

⟨ḥ| → ḥ⟩]
[ śam

[śam_3]{ind.}

⟨m|kh → ṅkh⟩]
[ kham

[kha]{n. sg. acc. \| n. sg. nom.}

⟨⟩]
[ dadhmau

[dham]{pft. ac. sg. 3 \| pft. ac. sg. 1}

⟨⟩]
[ pratāpavān

[pratāpavat]{m. sg. nom.}

⟨⟩]

Solution 12 : ✓
[ siṃha

[siṃha]{iic.}

⟨⟩]
[ nādam

[nāda]{m. sg. acc.}

⟨⟩]
[ vinadya

[vi-nadya { ca. pfp. [1] }[vi-nad]]{iic.}

⟨a|u → o⟩]
[ uccaiḥ

[ucca]{m. pl. i. \| n. pl. i.}

⟨ḥ| → ḥ⟩]
[ śam

[śam_3]{ind.}

⟨m|kh → ṅkh⟩]
[ kham

[kha]{n. sg. acc. \| n. sg. nom.}

⟨⟩]
[ dadhmau

[dham]{pft. ac. sg. 3 \| pft. ac. sg. 1}

⟨⟩]
[ pratāpavān

[pratāpavat]{m. sg. nom.}

⟨⟩]

Solution 33 : ✓
[ siṃha

[siṃha]{iic.}

⟨⟩]
[ nādam

[nāda]{n. sg. acc. \| n. sg. nom.}

⟨⟩]
[ vinadya

[vi-nad]{abs. \| ca. abs.}

⟨a|u → o⟩]
[ uccaiḥ

[uccais]{adv.}

⟨ḥ| → ḥ⟩]
[ śam

[śam_3]{ind.}

⟨m|kh → ṅkh⟩]
[ kham

[kha]{n. sg. acc. \| n. sg. nom.}

⟨⟩]
[ dadhmau

[dham]{pft. ac. sg. 3 \| pft. ac. sg. 1}

⟨⟩]
[ pratāpavān

[pratāpavat]{m. sg. nom.}

⟨⟩]

Solution 36 : ✓
[ siṃha

[siṃha]{iic.}

⟨⟩]
[ nādam

[nāda]{n. sg. acc. \| n. sg. nom.}

⟨⟩]
[ vinadya

[vi-nad]{abs. \| ca. abs.}

⟨a|u → o⟩]
[ uccaiḥ

[ucca]{m. pl. i. \| n. pl. i.}

⟨ḥ| → ḥ⟩]
[ śam

[śam_3]{ind.}

⟨m|kh → ṅkh⟩]
[ kham

[kha]{n. sg. acc. \| n. sg. nom.}

⟨⟩]
[ dadhmau

[dham]{pft. ac. sg. 3 \| pft. ac. sg. 1}

⟨⟩]
[ pratāpavān

[pratāpavat]{m. sg. nom.}

⟨⟩]

Solution 42 : ✓
[ siṃha

[siṃha]{iic.}

⟨⟩]
[ nādam

[nāda]{n. sg. acc. \| n. sg. nom.}

⟨⟩]
[ vinadya

[vi-nadya { ca. pfp. [1] }[vi-nad]]{iic.}

⟨a|u → o⟩]
[ uccaiḥ

[ucca]{m. pl. i. \| n. pl. i.}

⟨ḥ| → ḥ⟩]
[ śam

[śam_3]{ind.}

⟨m|kh → ṅkh⟩]
[ kham

[kha]{n. sg. acc. \| n. sg. nom.}

⟨⟩]
[ dadhmau

[dham]{pft. ac. sg. 3 \| pft. ac. sg. 1}

⟨⟩]
[ pratāpavān

[pratāpavat]{m. sg. nom.}

⟨⟩]

6 solutions kept among 45
Filtering efficiency: 88%

Additional candidate solutions

Solution 1 : ✓
[ siṃha

[siṃha]{iic.}

⟨⟩]
[ nādam

[nāda]{m. sg. acc.}

⟨⟩]
[ vinadya

[vi-nad]{abs. \| ca. abs.}

⟨a|u → o⟩]
[ uccaiḥ

[uccais]{adv.}

⟨ḥ| → ḥ⟩]
[ śam

[śam_3]{ind.}

⟨m|kh → ṅkh⟩]
[ kham

[kha]{n. sg. acc. \| n. sg. nom.}

⟨⟩]
[ dadhmau

[dham]{pft. ac. sg. 3 \| pft. ac. sg. 1}

⟨⟩]
[ pratāpa

[pratāpa]{iic.}

⟨⟩]
[ vān

[vāt { ppr. [2] ac. }[vā_2]]{m. sg. nom.}

⟨⟩]

Solution 2 : ✓
[ siṃha

[siṃha]{iic.}

⟨⟩]
[ nādam

[nāda]{m. sg. acc.}

⟨⟩]
[ vinadya

[vi-nad]{abs. \| ca. abs.}

⟨a|u → o⟩]
[ uccaiḥ

[uccais]{adv.}

⟨ḥ| → ḥ⟩]
[ śam

[śam_3]{ind.}

⟨m|kh → ṅkh⟩]
[ kham

[kha]{n. sg. acc. \| n. sg. nom.}

⟨⟩]
[ dadhmau

[dham]{pft. ac. sg. 3 \| pft. ac. sg. 1}

⟨⟩]
[ pratāpa

[pratāpa]{iic.}

⟨⟩]
[ vān

[vāt { ppr. [2] ac. }[vā_2]]{m. sg. voc.}

⟨⟩]

Solution 4 : ✓
[ siṃha

[siṃha]{iic.}

⟨⟩]
[ nādam

[nāda]{m. sg. acc.}

⟨⟩]
[ vinadya

[vi-nad]{abs. \| ca. abs.}

⟨a|u → o⟩]
[ uccaiḥ

[ucca]{m. pl. i. \| n. pl. i.}

⟨ḥ| → ḥ⟩]
[ śam

[śam_3]{ind.}

⟨m|kh → ṅkh⟩]
[ kham

[kha]{n. sg. acc. \| n. sg. nom.}

⟨⟩]
[ dadhmau

[dham]{pft. ac. sg. 3 \| pft. ac. sg. 1}

⟨⟩]
[ pratāpa

[pratāpa]{iic.}

⟨⟩]
[ vān

[vāt { ppr. [2] ac. }[vā_2]]{m. sg. nom.}

⟨⟩]

Solution 5 : ✓
[ siṃha

[siṃha]{iic.}

⟨⟩]
[ nādam

[nāda]{m. sg. acc.}

⟨⟩]
[ vinadya

[vi-nad]{abs. \| ca. abs.}

⟨a|u → o⟩]
[ uccaiḥ

[ucca]{m. pl. i. \| n. pl. i.}

⟨ḥ| → ḥ⟩]
[ śam

[śam_3]{ind.}

⟨m|kh → ṅkh⟩]
[ kham

[kha]{n. sg. acc. \| n. sg. nom.}

⟨⟩]
[ dadhmau

[dham]{pft. ac. sg. 3 \| pft. ac. sg. 1}

⟨⟩]
[ pratāpa

[pratāpa]{iic.}

⟨⟩]
[ vān

[vāt { ppr. [2] ac. }[vā_2]]{m. sg. voc.}

⟨⟩]

Solution 10 : ✓
[ siṃha

[siṃha]{iic.}

⟨⟩]
[ nādam

[nāda]{m. sg. acc.}

⟨⟩]
[ vinadya

[vi-nadya { ca. pfp. [1] }[vi-nad]]{iic.}

⟨a|u → o⟩]
[ uccaiḥ

[ucca]{m. pl. i. \| n. pl. i.}

⟨ḥ| → ḥ⟩]
[ śam

[śam_3]{ind.}

⟨m|kh → ṅkh⟩]
[ kham

[kha]{n. sg. acc. \| n. sg. nom.}

⟨⟩]
[ dadhmau

[dham]{pft. ac. sg. 3 \| pft. ac. sg. 1}

⟨⟩]
[ pratāpa

[pratāpa]{iic.}

⟨⟩]
[ vān

[vāt { ppr. [2] ac. }[vā_2]]{m. sg. nom.}

⟨⟩]

Solution 11 : ✓
[ siṃha

[siṃha]{iic.}

⟨⟩]
[ nādam

[nāda]{m. sg. acc.}

⟨⟩]
[ vinadya

[vi-nadya { ca. pfp. [1] }[vi-nad]]{iic.}

⟨a|u → o⟩]
[ uccaiḥ

[ucca]{m. pl. i. \| n. pl. i.}

⟨ḥ| → ḥ⟩]
[ śam

[śam_3]{ind.}

⟨m|kh → ṅkh⟩]
[ kham

[kha]{n. sg. acc. \| n. sg. nom.}

⟨⟩]
[ dadhmau

[dham]{pft. ac. sg. 3 \| pft. ac. sg. 1}

⟨⟩]
[ pratāpa

[pratāpa]{iic.}

⟨⟩]
[ vān

[vāt { ppr. [2] ac. }[vā_2]]{m. sg. voc.}

⟨⟩]

Solution 31 : ✓
[ siṃha

[siṃha]{iic.}

⟨⟩]
[ nādam

[nāda]{n. sg. acc. \| n. sg. nom.}

⟨⟩]
[ vinadya

[vi-nad]{abs. \| ca. abs.}

⟨a|u → o⟩]
[ uccaiḥ

[uccais]{adv.}

⟨ḥ| → ḥ⟩]
[ śam

[śam_3]{ind.}

⟨m|kh → ṅkh⟩]
[ kham

[kha]{n. sg. acc. \| n. sg. nom.}

⟨⟩]
[ dadhmau

[dham]{pft. ac. sg. 3 \| pft. ac. sg. 1}

⟨⟩]
[ pratāpa

[pratāpa]{iic.}

⟨⟩]
[ vān

[vāt { ppr. [2] ac. }[vā_2]]{m. sg. nom.}

⟨⟩]

Solution 32 : ✓
[ siṃha

[siṃha]{iic.}

⟨⟩]
[ nādam

[nāda]{n. sg. acc. \| n. sg. nom.}

⟨⟩]
[ vinadya

[vi-nad]{abs. \| ca. abs.}

⟨a|u → o⟩]
[ uccaiḥ

[uccais]{adv.}

⟨ḥ| → ḥ⟩]
[ śam

[śam_3]{ind.}

⟨m|kh → ṅkh⟩]
[ kham

[kha]{n. sg. acc. \| n. sg. nom.}

⟨⟩]
[ dadhmau

[dham]{pft. ac. sg. 3 \| pft. ac. sg. 1}

⟨⟩]
[ pratāpa

[pratāpa]{iic.}

⟨⟩]
[ vān

[vāt { ppr. [2] ac. }[vā_2]]{m. sg. voc.}

⟨⟩]

Solution 34 : ✓
[ siṃha

[siṃha]{iic.}

⟨⟩]
[ nādam

[nāda]{n. sg. acc. \| n. sg. nom.}

⟨⟩]
[ vinadya

[vi-nad]{abs. \| ca. abs.}

⟨a|u → o⟩]
[ uccaiḥ

[ucca]{m. pl. i. \| n. pl. i.}

⟨ḥ| → ḥ⟩]
[ śam

[śam_3]{ind.}

⟨m|kh → ṅkh⟩]
[ kham

[kha]{n. sg. acc. \| n. sg. nom.}

⟨⟩]
[ dadhmau

[dham]{pft. ac. sg. 3 \| pft. ac. sg. 1}

⟨⟩]
[ pratāpa

[pratāpa]{iic.}

⟨⟩]
[ vān

[vāt { ppr. [2] ac. }[vā_2]]{m. sg. nom.}

⟨⟩]

Solution 35 : ✓
[ siṃha

[siṃha]{iic.}

⟨⟩]
[ nādam

[nāda]{n. sg. acc. \| n. sg. nom.}

⟨⟩]
[ vinadya

[vi-nad]{abs. \| ca. abs.}

⟨a|u → o⟩]
[ uccaiḥ

[ucca]{m. pl. i. \| n. pl. i.}

⟨ḥ| → ḥ⟩]
[ śam

[śam_3]{ind.}

⟨m|kh → ṅkh⟩]
[ kham

[kha]{n. sg. acc. \| n. sg. nom.}

⟨⟩]
[ dadhmau

[dham]{pft. ac. sg. 3 \| pft. ac. sg. 1}

⟨⟩]
[ pratāpa

[pratāpa]{iic.}

⟨⟩]
[ vān

[vāt { ppr. [2] ac. }[vā_2]]{m. sg. voc.}

⟨⟩]

Solution 40 : ✓
[ siṃha

[siṃha]{iic.}

⟨⟩]
[ nādam

[nāda]{n. sg. acc. \| n. sg. nom.}

⟨⟩]
[ vinadya

[vi-nadya { ca. pfp. [1] }[vi-nad]]{iic.}

⟨a|u → o⟩]
[ uccaiḥ

[ucca]{m. pl. i. \| n. pl. i.}

⟨ḥ| → ḥ⟩]
[ śam

[śam_3]{ind.}

⟨m|kh → ṅkh⟩]
[ kham

[kha]{n. sg. acc. \| n. sg. nom.}

⟨⟩]
[ dadhmau

[dham]{pft. ac. sg. 3 \| pft. ac. sg. 1}

⟨⟩]
[ pratāpa

[pratāpa]{iic.}

⟨⟩]
[ vān

[vāt { ppr. [2] ac. }[vā_2]]{m. sg. nom.}

⟨⟩]

Solution 41 : ✓
[ siṃha

[siṃha]{iic.}

⟨⟩]
[ nādam

[nāda]{n. sg. acc. \| n. sg. nom.}

⟨⟩]
[ vinadya

[vi-nadya { ca. pfp. [1] }[vi-nad]]{iic.}

⟨a|u → o⟩]
[ uccaiḥ

[ucca]{m. pl. i. \| n. pl. i.}

⟨ḥ| → ḥ⟩]
[ śam

[śam_3]{ind.}

⟨m|kh → ṅkh⟩]
[ kham

[kha]{n. sg. acc. \| n. sg. nom.}

⟨⟩]
[ dadhmau

[dham]{pft. ac. sg. 3 \| pft. ac. sg. 1}

⟨⟩]
[ pratāpa

[pratāpa]{iic.}

⟨⟩]
[ vān

[vāt { ppr. [2] ac. }[vā_2]]{m. sg. voc.}

⟨⟩]